The Sum Of The Digits Of The Number [10^4N^2 + ^8 + 8] Where 'N' Is A Positive Integer, Is:?
Please help me urgent.
Home › Mathematics › The Sum Of The Digits Of The Number [10^4N^2 + ^8 + 8] Where 'N' Is A Positive Integer, Is:?
Please help me urgent.
-Anonymous
[10^4n^2 + ^8 + 8
= [10]^(4nx2x8x8]
= 10^512n
-Anonymous
= [10]^(4nx2x8x8]
= 10^512n
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