Solving For X In Exponential Equation.?
The question is as follows:
7^(-6x) = 49^(1-4x)
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The question is as follows:
7^(-6x) = 49^(1-4x)
-Anonymous
7^(-6x) = 49^(1-4x)
powers can be equated when bases are same.
So 49 can be written as 7^2
so 7^(-6x) = 7^[2(1-4x)]
so -6x = 2(1-4x)
-6x = 2 - 8x
2x = 2
x=1
-Anonymous
So 49 can be written as 7^2
so 7^(-6x) = 7^[2(1-4x)]
so -6x = 2(1-4x)
-6x = 2 - 8x
2x = 2
x=1
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