4x - 2y - z = -5
x - 3y + 2z = 3
3x + y - 2z = -5

A) (0, 1, 3)
B) (0, -1, 3)
C) (0, 1, -3)
D) (0, -1, -3)

2. If you were to use the elimination method to solve the following system, choose the new system of equations that would result after the variable z is eliminated in the first and second equations, then the second and third equations.
x - 3y - 3z = -13
x + 2y - z = -1
2x + 3y + 2z = 0

A) x - 3y = -13
-2x - 9y = -10

B) 2x + 3y = 0
4x + 7y = -2

C) -2x - 9y = -10
4x + 7y = -2

D) x - 3y = -13
2x + 3y = 0

3. If you were to use the substitution method to solve the following system, choose the new system of equations that would result if x was isolated in the second equation.
5x - 2y - z = 16
x + y + 4z = 6
3x + 2y + 6z = 16

A) -3y + 19z = -14
5y + 18z = -2

B) 7x + 7z = 28
x - 2z = 4

C) -7y - 21z = -14
-y - 6z = -2

D) 21x - 7y = 70
33x - 10y = 112


help me pleaseeee !!! :/

2)
x - 3y - 3z = -13
x + 2y - z = -1
2x + 3y + 2z = 0

x - 3y - 3z = -13
-3x - 6y + 3z = 3
-2x - 9y = -10

2x + 4y - 2z = -2
2x + 3y + 2z = 0
4x + 7y = -2

C)
-2x - 9y = -10
4x + 7y = -2