Multiply everything in the second parentheses by x
Multiply everything in the second parentheses by -1
Then combine like terms

(x – 1)(x2 + 5x + 2)
x^3 + 5x^2 + 2x - x^2 - 5x - 2
x^3 + 5x^2 - 1x^2 + 2x - 5x - 2
x^3 + 4x^2 - 3x - 2 <--- This is your answer!

(x-1)(x^(2)+5x+2)

Multiply each term in the first polynomial by each term in the second polynomial.
(x*x^(2)+x*5x+x*2-1*x^(2)-1*5x-1*2)

Multiply x by x^(2) to get x^(3).
(x^(3)+x*5x+x*2-1*x^(2)-1*5x-1*2)

Multiply x by 5x to get 5x^(2).
(x^(3)+5x^(2)+x*2-1*x^(2)-1*5x-1*2)

Multiply x by 2 to get 2x.
(x^(3)+5x^(2)+2x-1*x^(2)-1*5x-1*2)

Multiply -1 by x^(2) to get -x^(2).
(x^(3)+5x^(2)+2x-x^(2)-1*5x-1*2)

Multiply -1 by 5x to get -5x.
(x^(3)+5x^(2)+2x-x^(2)-5x-1*2)

Multiply -1 by 2 to get -2.
(x^(3)+5x^(2)+2x-x^(2)-5x-2)

According to the distributive property, for any numbers a, b, and c, a(b+c)=ab+ac and (b+c)a=ba+ca. Here, x^(2) is a factor of both 5x^(2) and -x^(2).
(x^(3)+(5-1)x^(2)+2x-5x-2)

To add integers with different signs, subtract their absolute values and give the result the same sign as the integer with the greater absolute value. In this example, subtract the absolute values of 5 and -1 and give the result the same sign as the integer with the greater absolute value.
(x^(3)+(4)x^(2)+2x-5x-2)

Remove the parentheses.
(x^(3)+4x^(2)+2x-5x-2)

According to the distributive property, for any numbers a, b, and c, a(b+c)=ab+ac and (b+c)a=ba+ca. Here, x is a factor of both 2x and -5x.
(x^(3)+4x^(2)+(2-5)x-2)

To add integers with different signs, subtract their absolute values and give the result the same sign as the integer with the greater absolute value. In this example, subtract the absolute values of 2 and -5 and give the result the same sign as the integer with the greater absolute value.
(x^(3)+4x^(2)+(-3)x-2)

Remove the parentheses.
(x^(3)+4x^(2)-3x-2)

Remove the parentheses around the expression x^(3)+4x^(2)-3x-2.
x^3+4x^2-3x-2