Qu?
a hammer is thrown vertically upwards towards the top of a roof of 16 m in height. What minimum initial velocity is required to get there?
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un martillo es arrojado verticalmente hacia arriba en dirección a la cumbre de un techo de 16 m de altura. ¿que velocidad inicial mínima se requirió para que llegara allá?
-Anonymous
Hmax=Vi(cuadrada)/ 2 x G
16m= Vi(cuadrada)/ 2 x 9.8m/seg(cuadrado)
16m= Vi (c)/19.6 m/seg(c)
16m x 19.6m/seg (c) = Vi(c)
(raiz cuadrada de)313.6 m(c)/s(c)=Vi
17.71=Vi
espero que haya servido :D
-Anonymous
16m= Vi(cuadrada)/ 2 x 9.8m/seg(cuadrado)
16m= Vi (c)/19.6 m/seg(c)
16m x 19.6m/seg (c) = Vi(c)
(raiz cuadrada de)313.6 m(c)/s(c)=Vi
17.71=Vi
espero que haya servido :D
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