factor..

3x^3 + 9x^2+6x

graph...
y=x^2-4x+3

alexis of symmetry:
vertez:
zeroes:

Domain of function; y=3+ [square root] x-2

3*x^3 + 9*x^2 + 6*x = 3*x*(x^2 + 3*x + 2) = 3*x*(x + 2)*x + 1) = 0

x1 = 0, x2 = - 2, x = - 1

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On "Function I Insert function", type x^2 - 4*x + 3, then "OK".

diff(x^2-4*x+3, x) = 2*x - 4

solve(2*x - 4 = 0)

x = 2, axis of symmetry.

f(x):=x^2-4 x+3

f(2) = - 1

point (2; - 1), Vertex

x^2 - 4*x + 3 = 0

(x - 3)*(x - 1) = 0

x = 3, x = 1

x - int: (3, 0), (1, 0)

y = 3 + sqrt(x - 2)

x - 2 ≥ 0

Domain: x ≥ 2, [2; + ∞)