How Is 21X^3/36X Divided By 7X/4X^2, X^4/3 And Not X^3/3?
I got x^3/3 but several people said it was x^4/3. I don't understand.
And is the answer to 3/2y+5/3y= 19/6y or do you just add it and get 8/5y
Home › Mathematics › How Is 21X^3/36X Divided By 7X/4X^2, X^4/3 And Not X^3/3?
I got x^3/3 but several people said it was x^4/3. I don't understand.
And is the answer to 3/2y+5/3y= 19/6y or do you just add it and get 8/5y
-Anonymous
And is the answer to 3/2y+5/3y= 19/6y or do you just add it and get 8/5y
Please take note that capital X used for times or multiplication.
= 21x^3/36x divided by 7x/4x^2
= ( 21x^3/36x) / ( 7x/4x^2)
= ( 21 X x^3/36x) / ( 7x/4x^2)
= ( 21 X x^3/36x) X ( 4x^2/7x)
= 21 X x^3/36x X 4x^2/7x
= 21 X x^3/9 X x/7x
= 3 X x^3/9 X x
= x^3/3
You are right. The answer is x^3/3
**************************************…
The answer to 3/2y+5/3y is 19/6y
Thank you
-Anonymous
= 21x^3/36x divided by 7x/4x^2
= ( 21x^3/36x) / ( 7x/4x^2)
= ( 21 X x^3/36x) / ( 7x/4x^2)
= ( 21 X x^3/36x) X ( 4x^2/7x)
= 21 X x^3/36x X 4x^2/7x
= 21 X x^3/9 X x/7x
= 3 X x^3/9 X x
= x^3/3
You are right. The answer is x^3/3
**************************************…
The answer to 3/2y+5/3y is 19/6y
Thank you
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