How Do You Prepare 1 Liter Of 1 Mol Of Mgso4 Solution From Mgso4.7H2O?
MgSO4.7H2O mass = (24 +32 +64 +14 +112) = 246 g / mol
M = moles / liter (moles = g / molecular mass) M = g / g = mass x Liters liters mass M x
g = M x mass x Liters
g = (1 mol / L) x (246 g / mol) X (1 l) = 246 g
Weight 246 g MgSO4.7H2O on a scale, I put in a flask! Liter of solution and add 1 liter of distilled water and stirred to dissolve the solute.
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