Flowers Vs Hoc Questions Help?
Mg heated mixture of CuO and Al dk no air. Pung in the following solid NaOH aq for dc balance when H2 and 672 ml X solids. X dissolved in HNO3 spills all that excess NO may come out looking 448 ml m
3 CuO + 2Al => Al2O3 + 3Cu
0,03mol 0,02mol 0,03mol
2NaOH + 2Al + 2H2O => 2NaAlO2 + 3H2
0,02mol 0,03mol
2NaOH + Al2O3 => 2NaAlO2 + H2O
3Cu + 8HNO3 => 3Cu(NO3)2 + 2NO + 4H2O
nNO = 0,448/22,4=0,02mol => nCu = 0,03mol =>nCuO =0,03mol=>m CuO=2,4g
=>nAl(pt1)=0,02mol=>mAl=0,02*27=0,54g
nH2=0,03mol=>nAl= 0,02mol=> mAl = 0,02*27=0,54g
=>m = 2,4+0,54+0,54= 3,48
làm hơi tắt, thông cảm
-Anonymous
0,03mol 0,02mol 0,03mol
2NaOH + 2Al + 2H2O => 2NaAlO2 + 3H2
0,02mol 0,03mol
2NaOH + Al2O3 => 2NaAlO2 + H2O
3Cu + 8HNO3 => 3Cu(NO3)2 + 2NO + 4H2O
nNO = 0,448/22,4=0,02mol => nCu = 0,03mol =>nCuO =0,03mol=>m CuO=2,4g
=>nAl(pt1)=0,02mol=>mAl=0,02*27=0,54g
nH2=0,03mol=>nAl= 0,02mol=> mAl = 0,02*27=0,54g
=>m = 2,4+0,54+0,54= 3,48
làm hơi tắt, thông cảm
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