Home › Mathematics › Find The Critical Numbers Of The Following Function...?
f(x) = (x^2 - 25)^3
-Anonymous
Differentiate...
f'(x) = 3(x² - 25)²(2x)
= 6x(x² - 25)²
Since critical points occur where f'(x) = 0 or dne...
0 = 6x(x² - 25)²
x = {±5, 0}
Since the intervals around x = ±5 don't change, these points are not critical. Therefore, x = 0.
http://www.wolframalpha.com/input/?i=6x%…
I hope this helps!
-Anonymous
f'(x) = 3(x² - 25)²(2x)
= 6x(x² - 25)²
Since critical points occur where f'(x) = 0 or dne...
0 = 6x(x² - 25)²
x = {±5, 0}
Since the intervals around x = ±5 don't change, these points are not critical. Therefore, x = 0.
http://www.wolframalpha.com/input/?i=6x%…
I hope this helps!
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