Exercise Of Arithmetic Progression?
The sum of three numbers in AP is 02.03 ^ 3m-4, the middle term is 2 ^ m I> 0. The value of m is:
(Got to give 2) If anyone can help me, I can not do this exerccio.Obrigado now!
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A soma de três números em PA é 3.2^3m-4, o termo médio é 2^m e m>0. O valor de m é:
(Tem que dar 2)Se alguém puder me ajudar, não consigo fazer este exercício.Obrigado desde já!
-Anonymous
(Tem que dar 2)Se alguém puder me ajudar, não consigo fazer este exercício.Obrigado desde já!
A Soma (a₁+a₂+a₃) = 3.2^(3m-4) e a₂ = 2^m
Como a₁ = a₂ - r e a₃ = a₂ + r temos:
(2^m - r) + (2^m) +(2^m + r) = 3.2^(3m-4)
2^m + 2^m +2^m -r + r = 3.2^(3m-4)
2^m + 2^m +2^m = 3.2^(3m-4)
3.2^m = 3.2^(3m-4)
2^m = 2^(3m-4)
Logo:
m = 3m-4
3m-m = 4
2m = 4
m = 4/2
m = 2
-Anonymous
Como a₁ = a₂ - r e a₃ = a₂ + r temos:
(2^m - r) + (2^m) +(2^m + r) = 3.2^(3m-4)
2^m + 2^m +2^m -r + r = 3.2^(3m-4)
2^m + 2^m +2^m = 3.2^(3m-4)
3.2^m = 3.2^(3m-4)
2^m = 2^(3m-4)
Logo:
m = 3m-4
3m-m = 4
2m = 4
m = 4/2
m = 2
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