Solve this using the zero product property:
2x(x + 2) = 0
2x = 0 OR x + 2 = 0
x = 0 OR x = -2
x = {-2, 0}

2x(x+2)=0;

first consider what value you replace x with would get you 0.
eg. 0 times any number = 0

so,

2 times what number = 0? 2(0) = 0
2(0)(0+2) = 0 (2) = 0 <-- plug in 0 into the equation; replace 0 with x

also,

-2+2 = 0

2(-2)(-2+2) = -4(0) = 0 <-- plug in -2 into the equation; replace -2 with x

x would have to be equal to 0 or -2