Home › Mathematics › 1/{Cos(X-A).Cos(A-B)}?
plzzz help me by integrating this troublesome question
-Anonymous
Correction : ... cos(a-b) should be cos (x-b).
_____________________________________
... ∫ { 1 / [ cos (x-a). cos (x-b) ] } dx
= [ 1 / sin (a-b) ] · ∫ { sin (a-b) / [ cos (x-a). cos (x-b) ] } dx
= csc (a-b) ∫ { sin [ (x-b) - (x-a) ] } / [ cos (x-a). cos (x-b) ] dx
= csc (a-b) ∫ { sin(x-b). cos(x-a) - cos(x-b). sin(x-a) } / [ cos(x-a). cos(x-b) ] dx ... Now Split
= csc (a-b) ∫ { [ tan (x-b) ] - [ tan (x-a) ] } dx
= csc (a-b) { ln | sec (x-b) | - ln | sec (x-a) | } + C
= csc (a-b) · ln | sec (x-b) / sec (x-a) | + C
= csc (a-b) · ln | cos (x-a) / cos (x-b) | + C ...................... Ans.
___________________________________
Happy To Help !
___________________________________
-Anonymous
_____________________________________
... ∫ { 1 / [ cos (x-a). cos (x-b) ] } dx
= [ 1 / sin (a-b) ] · ∫ { sin (a-b) / [ cos (x-a). cos (x-b) ] } dx
= csc (a-b) ∫ { sin [ (x-b) - (x-a) ] } / [ cos (x-a). cos (x-b) ] dx
= csc (a-b) ∫ { sin(x-b). cos(x-a) - cos(x-b). sin(x-a) } / [ cos(x-a). cos(x-b) ] dx ... Now Split
= csc (a-b) ∫ { [ tan (x-b) ] - [ tan (x-a) ] } dx
= csc (a-b) { ln | sec (x-b) | - ln | sec (x-a) | } + C
= csc (a-b) · ln | sec (x-b) / sec (x-a) | + C
= csc (a-b) · ln | cos (x-a) / cos (x-b) | + C ...................... Ans.
___________________________________
Happy To Help !
___________________________________
- worth 10 points and 5 stars!?" People I bought a router and got the cable that was put on the pc and the router the net works normal now I want reeconectar shape of the cab..."
- Where will you go after death any ideas?" In my personal mausoleum a href httpanswersyahoocomquestionindexqidAAZynhttpanswersyahoocomquestionindexqid..."
- Here who aja pake yg OL science telepathy?" I use telepathy science free LO tis tis a href httpanswersyahoocomquestionindexqidAAAwVcchttpanswersyahoocomquest..."

(1 votes, average: 4.00 out of 5, rated)